In a first example we start by adding 29 to the abacus. Next we add 75 to 29 by first adding 7 to 2 on rod B. Then we add the 5 to the 9 on rod C using the 10 pair addition rule. But here we notice that when we try to add 1 to the 9 on rod B we will again need to use a second 10 pair addition rule which is the Forward Double Rod movement. Add 1 to 9 on rod B we use a second 10 pair addition by adding 1 to 0 on rod A. Next we subtract 9, the 10 pair of 1, from 9 on rod B leaving 0 on rod B. Completing the first 10 pair addition we subtract 5, the 10 pair of 5, from 9 on rod C leaving 4 on rod C. The interim sum is now 104. Next we add 58 to 104 by first adding 5 to 0 on rod B. Then we add 8 to 4 on rod C using a 10 pair addition by adding 1 to 5 on rod B leaving 6 on rod B and subtracting 2, the 10 pair of 8, from 4 on rod C leaving 2 on rod C. The final answer is 162.