In the first example we start by adding 97 to the abacus. Next we add 58 to 97 by first adding 5 to 9 on rod B using a 10 pair addition by adding 1 to 0 on rod A and subtracting 5, the 10 pair complement of 5, from 9 on rod B. We add 8 to 7 on rod C using a 10 pair addition by adding 1 to 4 on rod B using a 5 pair adding 5 and subtracting 4 leaving 5 on rod B. Next we subtract 2, the 10 pair complement of 8, from 7 on rod C for an interim sum of 155. Next we subtract 57 from 155 by first subtracting 5 from 5 on rod B leaving 0 on rod B. Then we subtract 7 from 5 on rod C using a 10 pair subtraction. First subtract 1 from 0 on rod B by doing another 10 pair subtraction and subtracting 1 from 1 on rod A and adding 9, the 10 pair complement of 1, to 0 on rod B. Finish the movement by adding 3, the 10 pair complement of 7, to 5 on rod C for a final answer of 98.