In this first example we start by adding 17 to the abacus placing 1 on rod A and 7 on rod B. Next we add 47 to 17 by first adding 4 to 1 on rod A using a 5 pair adding 5 and subtracting 1, the 5 pair of 4, leaving 5 on rod A. Next we add 7 to 7 on rod B using the 10 pair addition rule. First add 1 to 5 on rod A leaving 6 on rod A. Then subtract 3, the 10 pair complement of 7, from 7 on rod B using a 5 pair adding 2 and subtracting 5 leaving 4 on rod A. The interim sum is now 64. Lastly we subtract 19 from 64 by first subtracting 1 from 6 on rod A leaving 5 on rod A. Next we subtract 9 from 4 on rod B using the 10 pair subtraction rule which will require the Reverse Double Five. First subtract 1 from 5 on rod A using a 5 pair adding 4, the 5 pair of 1, and subtracting 5 leaving 4 on rod A. Finally add 1, the 10 pair of 9, to 4 on rod B again using a 5 pair adding 5 and subtracting 4 leaving 5 on rod B. The final answer is 45.